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MCQ
What is the rate law for an SN2 reaction between CH3Br and OH-?
Chemistry
A Rate = k[CH3Br]
B Rate = k[OH-]
C Rate = k[CH3Br][OH-]
D Rate = k[CH3Br]^2[OH-]
Explanation

SN2 is bimolecular: both the substrate and nucleophile are involved in the rate-determining step, so Rate = k[CH3Br][OH-].

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