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MCQ
The de Broglie wavelength of a proton and an alpha particle accelerated through same potential are in ratio:
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A 1:1
B 2:1
C 1:2
D 4:1
Explanation

λ = h/√(2qVm). λp/λα = √(qα/qp) = √(4e/e) = 2. So ratio is 2:1.

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