Home / Chemistry / Question
MCQ
What is the rate law for an SN2 reaction between CH3Br and OH-?
Chemistry
A Rate = k[CH3Br]
B Rate = k[OH-]
C Rate = k[CH3Br][OH-]
D Rate = k[CH3Br]^2[OH-]
Explanation

SN2 is bimolecular: both the substrate and nucleophile are involved in the rate-determining step, so Rate = k[CH3Br][OH-].

Related MCQs

The number of moles in 36 grams of water is:
Chemistry View
Which of the following is used to convert an alcohol to an alkyl halide?
Chemistry View
What is the geometry of a d8 metal complex with a strong field ligand in square planar arrangement?
Chemistry View
Which element has the electron configuration [Ar] 3d10 4s2 4p5?
Chemistry View
Which of the following is a buffer solution?
Chemistry View
Which quantum number determines the orientation of an orbital in space?
Chemistry View