What is the activation energy if the rate doubles when temperature increases from 300 K to 310 K? (R = 8.314 J/mol/K)

MCQ

Chemistry

A 25.3 kJ/mol

B 50.6 kJ/mol

C 75.9 kJ/mol

D 101.2 kJ/mol

Explanation

Using Arrhenius: ln(k2/k1) = (Ea/R)(1/T1 - 1/T2). ln(2) = (Ea/8.314)(1/300 - 1/310). Ea = 0.693 x 8.314 x 300 x 310 / 10 = 52,886 J/mol â‰ˆ 50.6 kJ/mol.

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