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MCQ
The stopping potential for photoelectrons emitted by light of wavelength 4000 Å is: (φ = 2.0 eV)
Physics
A 1.1 V
B 2.3 V
C 3.1 V
D 0.5 V
Explanation

E = hc/λ = (12400 eV·Å)/(4000 Å) = 3.1 eV. Vstop = E - φ = 3.1 - 2.0 = 1.1 V

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