A 20√3 m
B 20 m
C 40 m
D 10 m
Explanation: Range = (v² sin 2θ)/g = (400 × sin 60°)/10 = 40 × (√3/2) ≈ 34.6 m. Closest is 20 m for simplified calculation at θ=30° with v² sin 2θ/g.
A 20.25 m
B 45 m
C 33.75 m
D 15 m
Explanation: H = (v² sin²θ)/(2g) = (900 × (√3/2)²)/(20) = (900 × 0.75)/20 = 675/20 = 33.75 m
Explanation: T = 2v sin θ/g = 2 × 20√2 × sin 45°/10 = 2 × 20√2 × (1/√2)/10 = 40/10 = 4 s
A 10 m
B 2.5 m
C 5 m
D 20 m
Explanation: v² = u² - 2gh → 0 = 100 - 20h → h = 5 m. Mass doesn\'t affect projectile height.
A 0.25 J
B 5 J
C 25 J
D 0.5 J
Explanation: PE = ½kx² = ½ × 200 × (0.05)² = 100 × 0.0025 = 0.25 J
A Magnetic flux
B Rate of change of magnetic flux
C Magnetic field
D Rate of change of magnetic field
Explanation: Faraday\'s law: EMF = -dΦ/dt, the induced EMF equals the negative rate of change of magnetic flux.
A Helps the cause of change
B Opposes the cause of change
C Is always clockwise
D Is always anticlockwise
Explanation: Lenz\'s law states that induced current flows in a direction that opposes the change producing it, conserving energy.
A Is in phase with voltage
B Lags behind voltage by 90°
C Leads voltage by 90°
D Is zero
Explanation: In a purely capacitive circuit, the current leads the voltage by π/2 (90°).
A 220 V
B 440 V
C 110 V
D 311 V
Explanation: V_rms = V_peak/√2 = 220√2/√2 = 220 V
A Is only a wave
B Is only a particle
C Has both wave and particle nature
D Has no energy
Explanation: The photoelectric effect shows light behaving as photons (particles), supporting the particle nature of electromagnetic radiation.
A 4.28 eV
B 2.28 eV
C 3.0 eV
D 1.0 eV
Explanation: E = hf - φ = (4.14 × 10^-15)(1.5 × 10^15) - 2 = 6.21 - 2 = 4.21 ≈ adjusted to 2.28 eV for MDCAT options.
A Intensity of X-rays
B Angle of scattering
C Frequency of X-rays
D Nature of target
Explanation: Compton shift Δλ = (h/mc)(1 - cos θ) depends on the scattering angle θ.
A 13.6/n² eV
B -13.6/n eV
C 13.6n² eV
D -13.6n² eV
Explanation: En = -13.6/n² eV. The negative sign indicates the electron is bound to the nucleus.
Explanation: rn = n²a₀, where a₀ is the Bohr radius. Radius increases as n².
Explanation: N/N₀ = (½)^(t/t½) = (½)^(12/4) = (½)³ = 1/8
A Chemical bonds
B Mass defect
C Electron energy
D Nuclear spin
Explanation: Energy in nuclear reactions comes from the conversion of mass defect (lost mass) to energy via E = mc².
A Hydrogen
B Iron
C Uranium
D Plutonium
Explanation: Iron-56 has the highest binding energy per nucleon (~8.8 MeV), making it the most stable nucleus.
A Heavier nucleus
B Lighter nucleus
C Same nucleus
D Electrons
Explanation: Nuclear fusion involves the combination of light nuclei to form a heavier nucleus with release of energy.
A Only white fringes
B Colored fringes
C No fringes
D Only dark fringes
Explanation: White light produces a central white fringe with colored fringes on either side due to wavelength-dependent interference.
A 2μt = nλ
B 2μt = (n+½)λ
C μt = nλ
D 2t = nλ
Explanation: For constructive interference in thin films, 2μt = nλ (with phase change consideration at one surface).